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0=600-140x+6x^2
We move all terms to the left:
0-(600-140x+6x^2)=0
We add all the numbers together, and all the variables
-(600-140x+6x^2)=0
We get rid of parentheses
-6x^2+140x-600=0
a = -6; b = 140; c = -600;
Δ = b2-4ac
Δ = 1402-4·(-6)·(-600)
Δ = 5200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5200}=\sqrt{400*13}=\sqrt{400}*\sqrt{13}=20\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-20\sqrt{13}}{2*-6}=\frac{-140-20\sqrt{13}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+20\sqrt{13}}{2*-6}=\frac{-140+20\sqrt{13}}{-12} $
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